Solving the Project Euler Problems – Problem 6

The sum of the squares of the first ten natural numbers is, 12 + 22 + … + 102 = 385.

The square of the sum of the first ten natural numbers is, (1 + 2 + … + 10)2 = 552 = 3025.

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

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This one oddly seems relatively simple. simply take a number, work out the sum of 1 to that number then square it, work out the sum of the squares of 1 to that number and find the difference between your 2 results. Job done!

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